Work out the length of X.
х
8 cm
15 cm

Using the Pythagorean theorem which states that;
a²+b²=c²
or
side (1) ²+side (2) ²=hypotenuse²
15²+8²=x²
225+64=x²
289=x²
Take the square root of both sides to get;
x=√289=17
x=17
Step-by-step explanation:
[tex] \longmapsto \: hypotenuse(h) = x \\ \longmapsto \: perpendicular(p) = 15cm \\ \longmapsto \: base(b) = 8cm \\ using \: pythagoras \: theorem \\ \hookrightarrow {h}^{2} = {p}^{2} + {b}^{2} \\\hookrightarrow {x}^{2} = ({15cm}^{2} + ({8cm})^{2} \\ x = \sqrt{225 {cm}^{2} + 64 {cm}^{2} } \\ \hookrightarrow \: x = \sqrt{289 {cm}^{2} } \\ \hookrightarrow \: x = 17cm [/tex]