A cube has an edge length of 3 inches.

a) Find the surface area and volume of the cube.

b) The cube is dilated by a scale factor of 0.5.
Find the surface area and volume of the image.

PLEASE HELP THIS IS DUE TOMORROW!!!

Respuesta :

Answer:

Question (a)

Surface area of a cube = [tex]6x^2[/tex]   (where [tex]x[/tex] is an edge length)

⇒ surface area = 6 × 3²

                         = 6 × 3 × 3

                         = 6 × 9

                         = 54 in²

Volume of a cube = [tex]x^3[/tex]   (where [tex]x[/tex] is an edge length)

⇒ volume = 3³

                 = 3 × 3 × 3

                 = 27 in³

Question (b)

To find the area of a dilated figure, simply multiply the original area by the scale factor squared:

Surface area = [tex]6x^2[/tex] × sf²  

                      = 54 × 0.5²

                      = 13.5 in²

To find the volume of a dilated figure, simply multiply the original volume by the scale factor cubed:

Surface area = [tex]x^3[/tex] × sf³

                      = 27 × 0.5³

                      = 3.375 in³