Trigonometry, due in a few hours, 100 pts

Answer:
a) 120°
b) 16√3 ≈ 27.7 cm²
Step-by-step explanation:
Each exterior angle of a regular polygon measures 360° divided by the number of sides. For a hexagon, the exterior angle is 360°/6 = 60°. That means the adjacent interior angle is 180°-60° = 120°.
Angle ABC measures 120°.
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The area of triangle ABC can be found using the formula ...
A = 1/2ab·sin(C) . . . . area of triangle with sides a, b, and angle C between them
A = 1/2(8 cm)(8 cm)sin(120°) = (32 cm²)(√3/2) = 16√3 cm²
The area of the triangle is 16√3 cm² ≈ 27.7 cm².
Answer:
∠ABC = 120°
ΔABC = 16√3 cm²
Step-by-step explanation:
Part (a)
Sum of interior angles of a regular polygon = (n - 2) × 180°
(where n is the number of sides)
⇒ Sum of interior angles of a regular hexagon = (6 - 2) × 180° = 720°
All the interior angles in a regular polygon are equal.
⇒ Interior angle = sum of interior angles ÷ number of sides
⇒ ∠ABC = 720° ÷ 6
⇒ ∠ABC = 120°
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Part (b)
Use the sine rule for area of a triangle:
[tex]\dfrac12ab \sin(C)[/tex]
(where a and b are the sides and C is the included angle)
Given:
Substituting values into the formula:
[tex]\implies \dfrac12\cdot 8 \cdot 8 \sin(120)=16\sqrt{3} \ \sf cm^2[/tex]