Respuesta :
For each question, we will use the equation:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where m₁ is the mass of the first ball, u₁ is the initial speed of the first ball, m₂ is the mass of the second ball and u₂ is the initial speed of the second ball, all before collision.
The right hand side contains final masses and final velocities after collision.
Movement to the right will be considered positive and movement to the left will be considered negative.
1. 20 x 20 + 40u₂ = 0
u₂ = -10 m/s
Ball B needs to be moving towards the left at 10 m/s
2. 30 x -10 + 10u₂ = 10 x -30 + 30 x 10
u₂ = 30 m/s to the right
3. 10 x 20 + m₂ x -20 = 10 x 20 x -2 + m₂ x 0
m₂ = 30 kg
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where m₁ is the mass of the first ball, u₁ is the initial speed of the first ball, m₂ is the mass of the second ball and u₂ is the initial speed of the second ball, all before collision.
The right hand side contains final masses and final velocities after collision.
Movement to the right will be considered positive and movement to the left will be considered negative.
1. 20 x 20 + 40u₂ = 0
u₂ = -10 m/s
Ball B needs to be moving towards the left at 10 m/s
2. 30 x -10 + 10u₂ = 10 x -30 + 30 x 10
u₂ = 30 m/s to the right
3. 10 x 20 + m₂ x -20 = 10 x 20 x -2 + m₂ x 0
m₂ = 30 kg
Answer:
For 1: The velocity of Ball B is 10m/s and is moving in left direction.
For 2: The velocity of Ball D is 30m/s and is moving in right direction.
For 3: The mass of Ball F is 30 kg.
Explanation:
Let us assume that ball moving in left direction has a negative sign and the ball moving in right direction has a positive sign.
In collision reaction, the momentum remains conserved. The equation for this follows:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
- For 1:
[tex]m_1,u_1\text{ and }v_1[/tex] = mass, initial velocity and final velocity of ball A
[tex]m_2,u_2\text{ and }v_2[/tex] = mass, initial velocity and final velocity of ball B.
We are given:
[tex]m_1=20kg\\u_1=20m/s\\v_1=0m/s\\m_2=40kg\\u_2=?m/s\\v_1=0m/s[/tex]
Putting values in above equation, we get:
[tex]20(20)+40(u_2)=20(0)+40(0)\\u_2=-10m/s[/tex]
The velocity of Ball B is 10m/s and is moving is left direction.
- For 2:
[tex]m_1,u_1\text{ and }v_1[/tex] = mass, initial velocity and final velocity of ball C
[tex]m_2,u_2\text{ and }v_2[/tex] = mass, initial velocity and final velocity of ball D.
We are given:
[tex]m_1=30kg\\u_1=-10m/s\\v_1=10m/s\\m_2=10kg\\u_2=?m/s\\v_1=-30m/s[/tex]
Putting values in above equation, we get:
[tex]30(-10)+10(u_2)=30(10)+10(-30)\\u_2=30m/s[/tex]
The velocity of Ball D is 10m/s and is moving is right direction.
- For 3:
[tex]m_1,u_1\text{ and }v_1[/tex] = mass, initial velocity and final velocity of ball E
[tex]m_2,u_2\text{ and }v_2[/tex] = mass, initial velocity and final velocity of ball F.
We are given:
[tex]m_1=10kg\\u_1=20m/s\\v_1=-40m/s\\m_2=?kg\\u_2=20m/s\\v_1=0m/s[/tex]
Putting values in above equation, we get:
[tex]10(20)+m_2(-20)=10(-40)+m_2(0)\\m_2=30kg[/tex]
The mass of Ball E is 30kg.