jeramyahmelton
contestada

Suppose the probability that it rains in the next two days 1/3 for tomorrow and 1/6"for the day after tomorrow. What is P(rain tomorrow, then rain the day after tomorrow)?

A.1/2
B.1/18
C.2/9
D.1/9

Respuesta :

TheHero
This events are separate , so the probability of both of which combined is the product of them.

Let P(A) rain tomorrow event
      P(B) rain after tomorrow event

P(A) = 1/3

P(B) = 1/6

P(A in B) = P(A) * P(B) = 1/3 * 1/6= 1/18   

Choice: (B)

Answer:

[tex]\frac{1}{18}[/tex]

Step-by-step explanation:

Probability that it rains tomorrow P(A)=  [tex]\frac{1}{3}[/tex]

Probability that it rains day after tomorrow P(B)= [tex]\frac{1}{6}[/tex]

So, P(rain tomorrow, then rain the day after tomorrow)

[tex]P(A) \times P(B)[/tex]

[tex]\frac{1}{3} \times \frac{1}{6}[/tex]

[tex]\frac{1}{18}[/tex]

Hence P(rain tomorrow, then rain the day after tomorrow) is [tex]\frac{1}{18}[/tex]

So, Option B is correct.

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