In a photograph, a house is 4 inches wide and 6 inches tall. The photograph is enlarged while keeping proportional dimensions, and the width of the house in the enlarged photograph is 9 inches. What is the height of the house in the enlarged photograph?

Respuesta :

Answer:

13.5 inches

Step-by-step explanation:

Since the width is enlarged by a specific amount, the height has the be enlarged by the same amount. 9÷4=2.25. Since the width was enlarged by 2.25, the height should be enlarged by the same amount. Multiply 6 and 2.25, and you would get 6×2.25=13.5.

Hope this helps!

The height of the house in the enlarged photograph is 13.5cm.

How to estimate height of the house in the enlarged photograph?

Since the width exists enlarged by a specific amount, the height contains the be enlarged by the exact amount.

Let the height be x.

[tex]$\frac{4}{6}=\frac{9}{x}[/tex]

Cross multiply

4x = 54

Divide both sides by 4

[tex]$\frac{4 x}{4}=\frac{54}{4}[/tex]

Simplify

[tex]$x=\frac{27}{2}[/tex]

To estimate undefined (singularity) points: x = 0.

Combine undefined points with solutions:

[tex]$x=\frac{27}{2}[/tex]

x = 13.5

Therefore, the height of the house in the enlarged photograph is 13.5cm.

To learn more about algebraic expression

https://brainly.com/question/4541471

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