we know is a semi-circle, so let us use the equation for the area of a circle instead, and then, half it
so, the diameter is 1100, meaning the radius is half that, or 550
so...[tex]\textit{area of a circle}=\pi r^2\qquad r=radius=\frac{diameter}{2}=\frac{1100}{2}=550
\\ \quad \\
\textit{area of a semi-circle}=\cfrac{\pi r^2}{2}\impliedby \textit{enclosed acres}
\\ \quad \\
\textit{circumference of a circle}=2\pi r
\\ \quad \\
\textit{circumference of a semi-circle}=\cfrac{2\pi r}{2}\impliedby \textit{linear feet of fence}[/tex]
