Answer:
10+51+17=78
Step-by-step explanation:
Alright, so at first I just took a random number and kept on working it out until I got the exact answer as 78. Finally, i got the third number as 17. Now, i know the third number is 7 more than the first so I have to subtract 17 and 7, 17-7=10. So the first number is 10. Ok, now i know that the second number is 3 times the third number (17) so you should multiply, 17x3=51. 51 is the 2nd number.
1st number=10
2nd number=51
3rd number=17
Add them, 10+51+17=78.
Answer:
Step-by-step explanation:
In the question we are given ,
So , we are assuming that ,
We are finding the solution by adding all these term and equating it with 78 because sum of these three numbers is equal to 78 .
Here we go ,
[tex] \longrightarrow \: x + 3(x + 7) + x + 7 = 78[/tex]
Step 1 : Solving the bracket part :
[tex] \longrightarrow \: \blue{x }+ \blue{ 3x} + \red{21} + \blue{ x} + \red{7 }= 78[/tex]
Step 2 : Adding like terms :
[tex] \longrightarrow \:5x + 28 = 78[/tex]
Step 3 : Transposing 28 to right hand side :
[tex] \longrightarrow \:5x = \green{78} - \green{28}[/tex]
Step 4 : Subtracting 28 from 78 :
[tex] \longrightarrow \:5x = 50[/tex]
Step 5 : Transposing 5 to right hand side :
[tex] \longrightarrow \:x = \cancel \frac{50}{5} [/tex]
Step 6 ; Cancelling 50 with 5 :
[tex] \longrightarrow \: \purple{\boxed{x = 10}}[/tex]
Therefore value of ,
Verification :
We are verifying our answer by adding the three numbers and it must be equal to 78 .
Therefore , our answer is correct .
