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1.) A catering service is making up trays of hors​ d'oeuvres. The hors​ d'oeuvres are categorized as​ inexpensive, average, and expensive. If the client must select 2 of the 6 ​inexpensive, 5 of the 7 ​average, and 3 of the 5 expensive hors​ d'oeuvres, how many different choices are​ possible?

2.)A food company is testing 5 chocolate chip​ cookies, 4 ​crackers, and 7 ​reduced-fat cookies. If it plans to market 1 of the chocolate chip​ cookies, 1 of the​ crackers, and 4 of the​ reduced-fat cookies, how many different combinations are​ possible?

from the 8 male and 8 female sales representatives for an insurance​ company, a team of 3 men and 4 women will be selected to attend a national conference on insurance fraud.
In how many ways can the team of 7 be​ selected?

Respuesta :

Using the combination formula, it is found that the number of possible outcomes are given by:

1. 3150

2. 700.

3. 3920.

What is the combination formula?

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Item 1:

We have combinations of 2 from 6, 5 from 7 and 3 from 5, all independent, hence we multiply them:

[tex]T = C_{6,2}C_{7,5}C_{5,3} = 15 \times 21 \times 10 = 3150[/tex]

3150 different choices are possible.

Item 2:

1 from 5, 1 from 4 and 4 from 7, hence:

[tex]T = C_{5,1}C_{4,1}C_{7,4} = 5 \times 4 \times 35 = 700[/tex]

700 different combinations are possible.

Item 3:

3 men from a set of 8, 4 women from a set of 8, hence:

[tex]T = C_{8,3}C_{8,4} = 56 \times 70 = 3920[/tex]

3920 ways to select the team of 7.

More can be learned about the combination formula at https://brainly.com/question/25821700