The energy required to completely boil a 5.05 g-sample of liquid water at its boiling point is 2.73 kcal.
Boiling is the process in which, upon absorbing energy in the form of heat, a substance goes from the liquid state to the gaseous state.
We have a 5.05 g-sample of liquid water. We can calculate the heat required to completely boil it using the following expression.
Q = ΔH°vap × m
Q = 0.540 kcal/g × 5.05 g = 2.73 kcal
where,
The energy required to completely boil a 5.05 g-sample of liquid water at its boiling point is 2.73 kcal.
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