Answer:
[tex]\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)}[/tex]
Step-by-step explanation:
Quadratic formula: [tex]\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]2x^2-1=3x+4\\\\2x^2-3x-5=0\\\\\\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)} \\\frac{3+-\sqrt{9+40} }{4}[/tex]
[tex]x = \frac{3+-7}{4}[/tex]
Hope this helps and God bless!
