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In which reaction at equilibrium will the point of equilibrium shift to the right when the pressure decreases at constant temperature


1. N2(g) + 3H2(g) - 2NH3(g)

2. H2(g) + Bra(o) - 2HBr()

3. CaCO3(s) - Cao(s) + CO2(g)

3. N2(g) + O2(g) - 2NO(9)

Respuesta :

Answer:3

Explanation: an increase in pressure will just place the point of equilibrium in the direction that fevers the formation of the fewer number of moles. A decrease in pressure will displace the point of equilibrium in the direction that favors the formation of a greater number of moles as a system attempts to return to equilibrium

The reaction CaCO3(s) →Cao(s) + CO2(g) at equilibrium will be shifted to the right when the pressure decreases at constant temperature.

What is equilibrium?

Chemical equilibrium can be defined as the state of a system where the concentration of the reactant, as well as the concentration of the products, as well as the concentration of the products, will not change over time and the system's characteristics also will not change.

It is well known that when the number of moles grows, equilibrium shifts to the side where the number of moles grows when pressure is reduced.

In this equation, CaCO3(s) →Cao(s) + CO2(g)

Number of moles in reactant side= 1

Number of moles in product side = 2

Hence, for this reaction equilibrium will be shifted in right side.

To know more about equilibrium click here.

https://brainly.com/question/13463225.

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