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A gas sample has a volume of 30.0 mL at a pressure of 1.53 atm. If the volume increases to 50.1 mL and the temperature remains constant, the new pressure in atms will be

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At constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.

Boyle's law

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question question;

  • Initial volume of the gas V₁ = 30.0mL = 0.03L
  • Initial pressure of the gas P₁ = 1.53atm
  • Final volume of the gas V₂ = 50.1mL = 0.0501L
  • Final pressure of the gas P₂ = ?

We substitute our given values into the expression above to determine the new pressure.

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.53atm × 0.03L ) / 0.0501L

P₂ = 0.0459Latm / 0.0501L

P₂ = 0.92atm

Therefore, at constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.

Learn more about Boyle's law here: brainly.com/question/1437490

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