Please help me with this. (Geometry)

Step-by-step explanation:
Pythagoras's rule: [tex]a^2 + b^2 = c^2[/tex] becomes [tex]x^2 + 10^2 = y^2[/tex]
If we say b = 10: [tex]b = 10 = \sqrt{c^2 - a^2} = \sqrt{y^2 - x^2}[/tex]
You only need to look at the left triangle
Which of the options follows Pythagoras's rule?
Let's try the options until we get the right one (in no particular order)
If we try: 3) x = 4 y = [tex]29\sqrt{2}[/tex]...
[tex]\sqrt{(29\sqrt{2})^2 - 4^4} = 7\sqrt{34} \neq 10[/tex]
If we try: 4) x = 16 y = 116...
[tex]\sqrt{116^2 - 16^2} = 20\sqrt{3} \neq 10[/tex]
If we try: 2) x = 16 y = 29...
[tex]\sqrt{29^2 - 16^2} = 3\sqrt{65} \neq 10[/tex]
If we try: 1) x = 4 y = [tex]2\sqrt{29}[/tex]...
[tex]\sqrt{(2\sqrt{29})^2 - 4^2} = 10[/tex]