The oxidation number for sulphur (S) in the given compound sulphur trioxide (SO₃) is +6.
Oxidation number of any element is define as the number of exchangeable electrons from the outermost shell of an element.
For the given compound SO₃ no charge is present on the whole molecule and oxidation state of oxygen atom is -2, and let we assume that the oxidation state of sulphur atom is x and we calculate for x as:
x + 3(-2) = 0
x - 6 = 0
x = +6
Hence the oxidation state of atom is +6.
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