The ball’s speed and direction at the lowest point of trajectory are; 3.1 m/s and swing to the same angle on the other side
We will assume that all of the motion will transfer to Kinetic Energy at the lowest point. Now, the difference in height will be;
Δh = (130 – 130*cos °5) = 0.49 cm
The change in PE is;
ΔP.E = mgΔh
ΔP.E = 9.8m/s² × 0.75kg × 0.049 m
ΔP.E = 0.36015 J
Formula for kinetic energy is;
K.E = ¹/₂*m*v²
From conservation of energy;
K.E = P.E
Thus;
¹/₂* 0.075 * v² = 0.36015
v = √[(0.36015 * 2)/0.075]
v = 3.1 m/s
Thus, the pendulum will swing to the same angle on the other side.
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