Please help! 30 BRAIN POINTS (if it reduces it's bcs a bot posted those random links)
After encountering another ‘syntax error’ a disgruntled programmer throws a mouse perpendicular to the ground and it explodes into 3 pieces. A 100 g piece travels at 1.2 m/s, and a 30 g piece travels at 0.80m/s. The third piece flies off at a speed of 0.75 m/s. If the angle between the first two pieces is 120 degrees calculate the momentum and direction of the third piece with respect to the 100 g piece.

The momentum and direction of the third piece with respect to the 100 g mass is determined by applying the principle of conservation of linear momentum.

Pi = Pf

where;

Pi is initial momentum
Pf is final momentum

0 = P₁ + P₂ + P₃

where;

P₁ is final momentum of the first piece
P₂ is final momentum of the second piece
P₃ is final momentum of the third piece

-P₃ = P₁ + P₂

-P₃x = P₁cosθ + P₂Cosθ --(1)

-P₃y = P₁sinθ + P₂sinθ --(2)

-P₃x = (0.1 x 1.2 x cos0) + (0.03 x 0.8 x cos120)

-P₃x = 0.12 - 0.012

-P₃x = 0.108 kgm/s

P₃x = -0.108 kgm/s

-P₃y = (0.1 x 1.2 x sin0) + (0.03 x 0.8 x sin120)

-P₃y = 0.0208 kgm/s

P₃y = -0.0208 kgm/s

Resultant momentum of third piece

[tex]P_3 = \sqrt{P_3x^2 + P_3y^2} \\\\P_3 = \sqrt{(-0.108)^2 + (-0.0208)^2} \\\\P_3 = 0.11 \ kgm/s[/tex]

Direction of third piece

[tex]tan \ \theta = \frac{P_3y}{P_3x} \\\\\theta = tan^{-1} (\frac{P_3y}{P_3x} )\\\\\theta = tan^{-1} (\frac{-0.0208}{-0.108} )\\\\\theta = 11\ ^0[/tex]

with respect to 100 g, direction of third piece is 11⁰

Learn more about momentum here: https://brainly.com/question/7538238