The magnitude of the acceleration of the robot that pushes the doll with a force of 0.3 N is; 1 m/s²
We are given;
Mass of the toy doll; m = 0.2 kg
Mass of the robot; M = 0.3 kg
Force applied by the robot; F = 0.3 N
The magnitude of the acceleration of the robot is derived from Newton's second law of motion;
F = ma
where;
a is the acceleration of the robot
Thus;
0.3 = 0.3a
a = 0.3/0.3
a = 1 m/s²
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