A toy doll and a toy robot are standing on a frictionless surface facing each other. the doll has a mass of 0.20 kg 0.20 kg , and the robot has a mass of 0.30 kg 0.30 kg . the robot pushes on the doll with a force of 0.30 n 0.30 n . the magnitude of the acceleration of the robot is

Respuesta :

The magnitude of the acceleration of the robot that pushes the doll with a force of 0.3 N is; 1 m/s²

How to find the magnitude of acceleration?

We are given;

Mass of the toy doll;  m = 0.2 kg

Mass of the robot; M = 0.3 kg

Force applied by the robot; F = 0.3 N

The magnitude of the acceleration of the robot is derived from Newton's second law of motion;

F = ma

where;

a is the acceleration of the robot

Thus;

0.3 = 0.3a

a = 0.3/0.3

a = 1 m/s²

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