Respuesta :
The total distance the considered fallilng object travels in 2 seconds is given by: Option C: 19.6 m
What are equations of motion?
There are three equation of motions that can be used when motion of the object is under constant acceleration and on a straight path.
They are listed below as:
[tex]v = u + at\\\\s = ut + \dfrac{1}{2} at^2\\\\v^2 = u^2 + 2as[/tex]
where the symbols have following meanings:
- u = initial velocity of the considered object
- v = final velocity of the object
- a = acceleration of the object
- s = distance traveled by the object in 't' time.
Here, assuming negligible air resistance, and ideal situations, the free fall of the considered object can be modeled by these equations of motion.
Here, according to sign convention, we have:
[tex]a = -g = -9.8 \: \rm m/s^2[/tex]
Due to free fall, we have: [tex]u = 0[/tex]
Thus, the net displacement (taking the window as origin) is given by equation:
[tex]s = \dfrac{-gt^2}{2}[/tex]
The distance that object traveles in 2 seconds is the absolute displacement it gets in 2 second of freefall.
This is obtained as:
[tex]D_2 =|s|_2 = \left| \dfrac{-9.8 (2)^2}{2} \right| = 19.6 \: \rm m[/tex]
Thus, the total distance the considered fallilng object travels in 2 seconds is given by: Option C: 19.6 m
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