The tension in the string at the 60-cm mark will be 0.9 N.The tension force is applied along the whole length of the wire, pulling energy equally on both ends.
The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.
The given data in the problem is;
The length of the stick is, L= 1.20 m =120 cm
T is the tension in the string at the 60-cm mark;
T₁ is the tension at the 20-cm mark
From the torque equilibrium law;
[tex]\rm mg(30)-T_2(40)+T_2 (40) =0 \\\\\ T_1(0)=mg (30)\\\\\ T_2(40)=1.2 (30) \\\\ T_2= 0.9 \ N[/tex]
Hence the tension in the string at the 60-cm mark will be 0.9 N.
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