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The heat of vaporization is 540 calories per gram. What is the minimum number of
calories needed to change 40.0 grams of water
at 100°C to steam at the same temperature and
pressure?

Respuesta :

Eduard22sly

The minimum number of calories needed to change 40 g of water at 100°C to steam is 21600 calories

Data obtained from the question

  • Mass of water (m) = 40 g
  • Heat of fusion (ΔHv) = 540 cal/g
  • Heat (Q) =?

The heat needed to vaporise the water at 100 °C can be obtained as follow:

Q = m × ΔHv

Q = 40 × 540

Q = 21600 calories

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