A Student Mixes 40. ML Of 0.10 M HBr(Aq) With 60. ML Of 0.10 M KOH(Aq) At 25°C. What Is The [OH-] Of The Resulting Solution?

After the complete neutralization reaction occurs, excess hydroxide ion is left unreacted and concentration of the hydroxide ion, [OH-] is 0.02 M.
The hydroxide ion concentration is the amount in moles of hydroxide ion in a solution.
The hydroxide ion concentration is written as [OH-].
The equation of the reaction is given below:
[tex]HBr(aq) + KOH(aq) \rightarrow KBr(aq) + H_2O(l) \\ [/tex]
1 mole of HBr reacts with 1 mole of KOH
Moles of HBr = 40 mL × 0.1 M = 4 mmmoles
Moles of KOH = 60 mL × 0.1 M = 6 mmoles
Moles of [OH-] = 6 - 4 = 2 mmoles
Volume of solution = 100 mL
[OH-] = 2mmoles/100 mL = 0.02 M
Therefore, the concentration of the hydroxide ion, [OH-] is 0.02 M.
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