Answer:
x = -9, -3
Step-by-step explanation:
[tex] {x }^{2} + 12x + 27 = 0[/tex]
[tex](x + 3)(x + 9) = 0[/tex]
x = -3, -9
Answer:
-3 and -9
Step-by-step explanation:
Standard quaratic form: a² + bx + c = 0
x² + 12x + 27 = 0
find 2 numbers that multiply to 27 (the c-value), but add to 12(the b-value);
The numbers will be 9 and 3, since;
9 x 3 = 27
9 + 3 = 12
Now we can put these numbers in the standard factor form: (x + p) (x + q);
(x + 9) (x + 3) = 0
Now we can set each part equal to 0 and solve;
x + 9 = 0 => x = -9
x + 3 = 0 => x = -3
So the roots are;
-3 and -9
Hope this helps!
