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In a different plan for area​ codes, the first digit could be any number from 4 through​ 8, the second digit was either 0, 1, or 2​, and the third digit could be any number 4 except With this​ plan, how many different area codes are​ possible?

Respuesta :

Answer:

135 choices

Step-by-step explanation:

5 choices for 1st dig

3 choices for 2nd dig

9 choices for third digit

5 x 3 x 9 = 135

Answer:

135

Step-by-step explanation:

But, for the last digit that is go from 0-9 except the 4

So it also depends on the range for the last digit

Hope this helped! :)

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