The molar solubility of CoS is 5.0 x 10-22 mol l-1 in pure water. Calculate the Ksp for Cos.
A-1.6 × 10-35
B-2.5x 10-43
C-4.7 x 10-6
D-5.0 x 10-22
E-2.2 x 10-11

Respuesta :

Answer:

B

Explanation:

Write the dissociation reaction of solid CoS:
[tex]\displaystyle \text{CoS}_\text{(s)} \rightleftharpoons \text{Co}_\text{(aq)}^{2+} + \text{S}_\text{(aq)}^{2-}[/tex]

The Ksp expression is hence:
[tex]\displaystyle K_{sp} = [\text{Co}^{2+}][\text{S}^{2-}][/tex]

If the molar solubility of CoS is 5.0 × 10⁻²² mol L⁻¹ (M), then 5.0 × 10⁻²² M of Co²⁺ and S²⁻ also forms. Hence, the value of Ksp is:
[tex]\displaystyle \begin{aligned} K_{sp} & = [\text{Co}^{2+}][\text{S}^{2-}] \\ \\ & = (5.0\times 10^{-22})^2 \\ \\ & = 2.5\times 10^{-43}\end{aligned}[/tex]

In conclusion, the answer is B.