Answer:
About 326 K.
Explanation:
Recall the ideal gas law:
[tex]\displaystyle PV = nRT[/tex]
Where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.
Because we want to solve for temperature T:
[tex]\displaystyle T = \frac{PV}{nR}[/tex]
Substitute and evaluate. R has a value of 0.08206 L-atm/mol-K:
[tex]\displaystyle \begin{aligned} T & = \frac{(2.25\text{ atm})(25.0\text{ L})}{(2.10\text{ mol})\left(\dfrac{0.08206\text{ L - atm}}{\text{mol - K}}\right)} \\ \\ & = 326\text{ K}\end{aligned}[/tex]
In conclusion, the temperature of the gas will be about 326 K.
