The magnitude and direction of the elevator’s acceleration for the scale readings are; 0.6033 m/s² upwards and -1.264 m/s² downwards
A) We are given;
Weight of man; W = 683 N
Mass is gotten from;
m = W/g
where g is acceleration due to gravity = 9.81 m/s²
m = 683/9.81
m = 69.62 kg
Now, scale reading of lift is w = 725 N. Thus;
Apparent weight = 725 - 683
Apparent weight = 42 N which is is the force that acts on the body which generates the acceleration.
Thus, acceleration is;
a = 42/69.62
a = 0.6033 m/s² upwards
B) At scale reading of 595 N;
Apparent weight = 595 - 683 = -88 N
Acceleration;
a = -88/69.62
a = -1.264 m/s² downwards
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