Answer:
43 students and 11 chaperones
Step-by-step explanation:
Let a = number of chaperones or adults
Let s = number of students
1) We could set up two equations and solve them simultaneously using the substitution or the elimination method.
s + a = 54
8a + 6.50s = 367.50
I choose the substitution method.
2) Solve for s or y. I choose s.
a = 54 - s
8(54 - s) + 6.50s = 367.50
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432 - 8s + 6.50s = 367.50
432 - 1.50s = 367.50
-1.50s = 367.50 - 432
-1.50s = -64.50
s = [tex]\frac{-64.50}{-1.50}[/tex]
s = 43
3) Substitute the result into one of the two equations above. I choose the first one.
43 + a = 54
a = 54 - 43
a = 11
