[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
Solution -
[tex]Area\: of \:equilateral \:triangle\: = \: \frac{ \sqrt{3} }{4} a {}^{2} \\ \\ \implies \frac{ \sqrt{3}}{4} \times 14^{2} \\ \\ \implies \: \frac{ \sqrt{3} }{\cancel4} \times \cancel{196} \\ \\ \implies \: \sqrt{3} \times 49 \\ \\ \implies \: \bold\blue{49 \sqrt{3} \:units {}^{2}} [/tex]
Further ,
value of [tex]\bold\orange{\sqrt{3} = 1.732}[/tex]
therefore ,
[tex]Area = 49 \times 1.732 \\ \\ \implies \: \bold\red{84.69 \: units {}^{2} \: (approx.)}[/tex]
hope helpful :D
