The area of a gymnasium is 956 yd2. The width of the gymnasium is 4 yd longer than its length. Find the length and width of the gymnasium (round to the nearest yard). Include a labeled diagram in your work for full credit?

Respuesta :

Answer:

L = 29

w = 33

Step-by-step explanation:

  Area = w × L

           = (L + 4) × L

⇔ 956 = L² + 4L

⇔ 956 = (L + 2)² − 4

⇔ 956 + 4 = (L + 2)²

⇔ 960 = (L + 2)²

[tex]\Leftrightarrow L+2=\sqrt{960}[/tex]

[tex]\Leftrightarrow L+2=30.983866769659[/tex]

[tex]\Longrightarrow L+2 \approx 31[/tex]

[tex]\Longrightarrow L \approx 29[/tex]

[tex]\Longrightarrow w=L+4 \approx 29+4\approx33[/tex]

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