Find the nth term of this number sequence
7, 10, 13, 16, ...
help please !!

Answer:
[tex]a_{n}[/tex] = 3n + 4
Step-by-step explanation:
there is a common difference between consecutive terms , that is
10 - 7 = 13 - 10 = 16 - 13 = 3
this indicates the sequence is arithmetic with nth term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 7 and d = 3 , then
[tex]a_{n}[/tex] = 7 + 3(n - 1) = 7 + 3n - 3 = 3n + 4
Answer:
The nth term = 3n + 4.
Step-by-step explanation:
The formula for the nth term of an arithmetic progression is a(n) = dn + a(1) - d.
So this breaks down simply to,
a(n) = dn + a(1) - d a(n) = 3n + 7 - 3 a(n) = 3n + 4