1 .
a. Solve by elimination method.
x+y = 6 ; 2x - y = 3

b. Solve by substitution method.
2x - y = 7 , y = 3x

c. Solve
x^2 +(1 /16 ) = x / 2

2 . Factorize
a. a^2 - 2a - 2b - b^2
b. a^4 - 3a^2 + 1

Respuesta :

Answer:

1a. x=3 y=3

1b. x=-7 y=-21

1c. x=¼

2a. a(a-2)-b(2+b)

2b. a²(a²-3)+1

Ver imagen guyhasoos

Step-by-step explanation:

a .

x + y = 6

+

2x - y = 3

3x = 9

3x/3 = 9/3

x = 3

x + y = 6

y = 6 -x

y = 6 - 3

y = 3

b.

2x - y = 7

+

y = 3x

2x = 3x + 7

2x - 3x = 7

x = -7

y = 3x

y = 3(-7)

y = -21

c.

[tex] {x}^{2} + \frac{1}{16} = \frac{x}{2} [/tex]

[tex] {x}^{2} + \frac{1}{16} - \frac{x}{2} = 0[/tex]

[tex]16( {x}^{2} - \frac{x}{2} + \frac{1}{16} ) = 0[/tex]

[tex]16 {x}^{2} - 8x + 1 = 0[/tex]

[tex](4x - 1)(4x - 1) = 0[/tex]

[tex]x = \frac{1}{4} [/tex]

2.

a.

[tex] {a}^{2} - 2a - 2b - {b}^{2} [/tex]

[tex]a(a - 2) - b(b + 2)[/tex]