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There are 5 blue birds, 6 green ones and 3 black ones. If I randomly catch 2 birds, what is the probability the first bird is black and the second is green?​

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Answer:

So you must first get the total of all the birds, which is going be a fraction of course , that being 14/14 birds in total, since there are only 3 black birds the probability of me getting a black one 3/14 because there are fourteen in total, and the probability for the green birds is 6/14.

The combined probability that the first bird is black and the second is green is 0.0918

What is Probability?

Probability is the likeliness of an event to happen.

Total Blue birds = 5

Total Green birds = 6

Total Black birds = 3

Total birds = 14

The probability of selecting two birds such that the first bird is black and the second is green.

Probability = ( No. of the desired outcome )/( Total outcomes)

The probability of selecting black bird is 3/14

The probability of selecting green bird is 6/14

Therefore, the combined probability that the first bird is black and the second is green is

= (3/14) * (6/14)

= 18/196

= 0.0918

To know more about Probability

https://brainly.com/question/11234923

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