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Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4
Given that 61µg of aluminum phosphate precipitate formed, calculate the micromoles of aluminum ions in 50 mL of river water. (1µg = 1 x 10^(-6)g)

Respuesta :

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

  • 27+31+16(4)
  • 58+48
  • 106u

Moles of AlPO_4

  • 61µg/106
  • 0.000061/106
  • 5.75×10^{-7}
  • 57.5µmol

Moles of Al3+=57.5µmol

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