Respuesta :

Answer:

FJ = 32

IJ = 24

FG = 48

Step-by-step explanation:

Getting Started with FG

[tex]\frac{IH}{AB} =\frac{FG}{ED}[/tex]

[tex]\frac{72}{36} =\frac{FG}{24}[/tex]

[tex]\frac{FG}{24} =2[/tex]

[tex]FG=24(2)=48[/tex]

The proportion between polygons is 2:1

[tex]IJ=2CB[/tex]

[tex]IJ=2(12)=24[/tex]

[tex]FJ=2BC=2(16)=32[/tex]

Hope this helps

Answer:

FJ = 32

IJ = 24

FG = 48

Step-by-step explanation:

Given:  HGFJI ~ AEDCB

From inspection of the diagram, the corresponding sides are:

HG~AE

FG~DE

FJ~DC

IJ~CB

IH~BA

The only pair of sides that both have side lengths are IH and BA.  Therefore, we can use these to figure out the scale factor of dilation.

IH = 72   and   BA = 36

⇒ IH/BA= 72/36 = 2

Therefore, HGFJI is an enlargement of AEDCB by a scale factor of 2

If HG = 56

⇒ AE = 56 ÷ 2 = 28

If DE = 24

⇒ FG = 24 × 2 = 48

If DC = 16

⇒ FJ = 16 × 2 = 32

If CB = 12

⇒ IJ = 12 × 2 = 24