Answer:
[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
the question asks us to rationalise the given term ! thus , we'll just have to remove the √3 from th denominator anyhow !
let's start ~
[tex] \frac{2 \sqrt{5} }{7 - \sqrt{3} } \\ \\ \implies \: \frac{2 \sqrt{5} }{7 - \sqrt{3} } \: \times \: \frac{7 + \sqrt{3} }{7 + \sqrt{3} } = \frac{14 \sqrt{5} + 2 \sqrt{15} }{(7) {}^{2} - ( \sqrt{3) {}^{2} } } \\ \\ \implies \frac{14 \sqrt{5} + 2 \sqrt{15} }{49 - 3} \\ \\ \implies \frac{14 \sqrt{5} + 2 \sqrt{15} }{46} \\ \\ \implies \: \frac{\cancel{2}(7 \sqrt{5{} } \: + \sqrt{15} )}{\cancel{46} } \\ \\\bold\red{ \implies \: \frac{7 \sqrt{5} + \sqrt{15} }{23}}[/tex]
hope helpful :D
