Answer:
[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
the question asks us to rationalise the given expression ! thus , we'll just have to remove the √7 from the denominator by any means.
well , let's start ~
[tex] \frac{2 \sqrt{3} }{ \sqrt{7 } - 3} \\ \\ \implies \: \frac{2 \sqrt{3} }{ \sqrt{7} - 3} \: \times \: \frac{ \sqrt{7} + 3}{ \sqrt{7} + 3} = \frac{2 \sqrt{21} + 6 \sqrt{3} }{( \sqrt{7) } {}^{2} - (3) {}^{2} } \\ \\ \implies \: \frac{2 \sqrt{21} + 6 \sqrt{3} }{7 - 9} \\ \\ \implies \: \frac{2 \sqrt{21} + 6 \sqrt{3} }{2} \\ \\ \implies \: \frac{\cancel{2}( \sqrt{21} + 3 \sqrt{3)} }{\cancel{2} } \\ \\\bold\red{ \implies \: \sqrt{21 } + 3 \sqrt{3}} [/tex]
hope helpful :D
