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A beaker of (liquid) water has been heated to its boiling point.
Calculate the mass of water which will evaporate when an additional
565 kJ of energy is transferred to the water. The specific latent heat
of vaporisation of water is 2.26 MJ/kg (2,260,000 J/kg).

Respuesta :

pstnonsonjoku

Latent heat can not be detected by a thermometer. The mass of water lost is 0.25 g.

What  is latent heat?

The latent heat is the heat that can not be detected by a thermometer but it acts to break the intermolecular bonds in a substance.

Now we know that;

Heat added = 565 * 10^3 J

Heat of vaporization of water = 2,260,000 J/kg

H = mL

m = H/L

m = 565 * 10^3 J/ 2,260,000 J/kg

m = 0.25 g

Learn more about latent heat: https://brainly.com/question/13428994

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