Respuesta :

iuynsm

Answer:

SOLUTION:-

  • Let,last year population be x.
  • We have last year population+Increased population=10,800

[tex]x + 8\% \: of \: x = 10800[/tex]

[tex]\displaystyle{x + \frac{8x}{100} = 10800 }[/tex]

[tex]\displaystyle{ \frac{100x + 8x}{100} = 10800}[/tex]

[tex]\displaystyle{ \frac{108x}{100} = 10800}[/tex]

[tex]108x = 10800 \times 100[/tex]

[tex]108x = 1080000[/tex]

[tex]x = \displaystyle{ \frac{1080000}{108} }[/tex]

[tex]x = 10000[/tex]

Therefore,required last year population=10000

tehsilkhan2008

Answer:

The Correct Answer is 10,000.

Step-by-step explanation:

Becuase The Question itself is providing us that this year it increased by 8%. Then the said that the total population for this year is 10,800. So, that tells us that the 8% equal 800. 10,000+800=10,800.

10,800-800=10,000

The correct answer is 10,000.

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