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Point A has coordinates (0,4).
Point B has coordinates (1,6).
Point C has coordinates (2,0).
Find an equation of the line that passes through C and is perpendicular to AB.
equation needs to be in the form ax+by= c
a and b need to he integers ASAP PLS HELP

Respuesta :

Answer:

x - 6y - 2 = 0

Step-by-step explanation:

Let “m” be the slope of line AB

and “a” be the slope of the line that passes through C and is perpendicular to AB

Then

[tex]m = \frac{6-0}{1-2} =-6[/tex]

The second line is perpendicular to AB

then

m × a = -1

then

-6 × a = -1

then

[tex]a=\frac{1}{6}[/tex]

C(2,0) lies on the line of equation y=ax+b

⇔ C(2,0) lies on the line of equation y=(1/6)x+b

⇔ 0 = (1/6)×2 + b

Then b= -1/3

Therefore Our equation is :

y = (1/6)x - 1/3

⇔ 6y = x - 2

⇔ x - 6y - 2 = 0

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