Respuesta :
given:
[tex]2 {ab}^{2} + {8a}^{2} b[/tex]
solution:
[tex]2ab(b + 4a)[/tex]
to factorise first, find the highest common factor of each of the terms in the expression then, write the highest common factor (HCF) in front of any brackets atlast, fill in each term in the brackets by multiplying out.
Answer:
2ab(b+4a)
Step-by-step explanation:
I think you typed the question wrong so I will type it again in the correct format:
factorise fully 2ab²+8a²b
As we can see the highest number that goes into both terms is 2.
As we can also see a to the power of 1 is the highest power of a that goes into both terms.
As we can also see b to the power of 1 is the highest of b that goes into both terms.
So outisde the bracket will be 2ab.
Now we divide 2ab² by 2ab to get the first part of the bracket.
Then we divide 8a²b by 2ab to get the second part of the bracket.
2ab(b+4a)
Therefore our final answer is 2ab(b+4a)
Hope this helped and brainliest please
