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a rescue diver of mass 89 kg jumps from a hovering helicopter into the ocean below, what is the diver's speed (in m/s) when he hits the water

Respuesta :

Answer:

Need the HEIGHT of the helicopter to complete this answer

Explanation:

PE  (=mgh) is converted to KE  ( = 1/2 mv^2 )

mgh = 1/2 m v^2

gh = 1/2 v^2

v^2 = 2 gh

v = sqrt (2gh) = sqrt ( 2 * 9.8 * h)

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