Respuesta :

#1

[tex]\\ \rm\Rrightarrow \dfrac{WX}{UV}=\dfrac{HI}{FE}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{WX}{16}=\dfrac{10}{8}[/tex]

[tex]\\ \rm\Rrightarrow WX/2=10[/tex]

[tex]\\ \rm\Rrightarrow WX=20[/tex]

Again

#2

[tex]\\ \rm\Rrightarrow \dfrac{WX}{UT}=\dfrac{HI}{FG}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{20}{20}=\dfrac{10}{FG}[/tex]

[tex]\\ \rm\Rrightarrow FG=10[/tex]

semsee45

Answer:

WX = 20

FG = 10

Step-by-step explanation:

If EFGHI ~ VUTXW

then:

  • EF~VU
  • FG~UT
  • GH~TX
  • HI~XW
  • IE~WV

The only pair of sides that both have measures is EF and VU

EF = 8

VU = 16

VU/EF = 16/8 = 2

Therefore, VUTXW is enlargement of EFGHI by a scale factor of 2.

As HI = 10

⇒ WX = 10 × 2 = 20

As UT = 20

⇒ FG = 20 ÷ 2 = 10

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