The distance between the points (3,4) and (-2,-1) is found being 5√2 units.
What is the distance between two points ( p,q) and (x,y)?
The shortest distance(length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
[tex]D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]
We've to find the distance between two points
(p,q) = (3,4)
and (x,y) = (-2, -1)
We get it as:
[tex]D = \sqrt{(x-p)^2 + (y-q)^2}\\\\D = \sqrt{(-2-3)^2 + (-1-4)^2} \\\\D = \sqrt{5^2 + 5^2} = 5\sqrt{2} \: \rm units[/tex]
Thus, the distance between the points (3,4) and (-2,-1) is found being 5√2 units.
Learn more about distance between two points here:
brainly.com/question/16410393
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