Answer:
Use Substitution.
Plug in 2x-3 in place of y in the second equation.
4x - 3(2x-3) = 31
4x - 6x + 9 =31
-9 -9
-----------------------
-2x=22 so x=-11
Then, y=2(-11)-3, so y=-25
So the solution would be (-11,-25).
Step-by-step explanation:
is the variable alone?
No
what is it attached to?
you always do adding or subtracting first so it is attached to 3
How is it attached?
by subtraction
what is the inverse operation?
it is addition
then all you do is the same thing but with multiplication or division
Hi!
We can solve this using the substitution method.
Given:
[tex]y=2x-3\\4x-3y=31[/tex]
Using the first question, we know that [tex]y[/tex] is equal to [tex]2x-3[/tex], so we can simply plug that value in to the second equation, like so:
[tex]4x-3(2x-3)=31[/tex]
Now, we can algebraically solve this for [tex]y[/tex]
[tex]4x-3(2x-3)=31[/tex]
Distribute.
[tex]4x-6x+9=31[/tex]
Add like terms.
[tex]-2x+9=31[/tex]
Subtract [tex]9[/tex] from both sides.
[tex]-2x=22[/tex]
Divide both sides by [tex]-2[/tex]
[tex]x=-11[/tex]
Now plug in that value to the first equation:
[tex]y=2(-11)-3[/tex]
Multiply.
[tex]y=-22-3[/tex]
Subtract.
[tex]y=-25[/tex]
The solution is (-11, -25)
