Answer:
12 H, 18 O, 6 C
Explanation:
[tex]6H_{2} O + 6CO_{2} -- > C_{6}H_{12} + 6O_{2}\\[/tex]
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first, we'll fo the h on the first equation: [tex]6H_{2}[/tex]
multiply the 6 and 2 to get twelve.
in the second equation, we see that there is [tex]H_{12}[/tex]
so, in both there are 12 H.
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Now we'll do O.
in the first equation we have [tex]6O + 6O_{2}[/tex]
so we have 6 + (6*2) or 6 + 12, which gives us 18
in the second equation we have [tex]O_{6} + 6O_{2}[/tex]
it's basically the same thing, just written differently, so we have 18.
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Finally, C.
In the first equation, we have [tex]6C[/tex]
in the second [tex]C_{6}[/tex], again, same thing expressed differently.
both have 6 C.
