6.
A mobile welding machine of mass 80 kg was rolling freely on a horizontal surface
at speed of 5 m/s when locks to its castor wheels are applied, causing all four wheels
to stop rotating. The machine skidded a distance s-4 m before coming to rest.
Determine
the magnitude of normal reaction of each wheel
(b) the coefficient of kinetic friction between the wheels and the ground.

Question

26-04-2022
Engineering

contestada

6.
A mobile welding machine of mass 80 kg was rolling freely on a horizontal surface
at speed of 5 m/s when locks to its castor wheels are applied, causing all four wheels
to stop rotating. The machine skidded a distance s-4 m before coming to rest.
Determine
the magnitude of normal reaction of each wheel
(b) the coefficient of kinetic friction between the wheels and the ground.

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shrutiagrawal1798 shrutiagrawal1798 · Answer 1 · 2022-05-05T14:22:56+02:00

The magnitude of reaction for the wheel is 250 N. The coefficient of kinetic energy between the wheel and ground is 0.32.

What is friction?

The friction is given as the stop force acted by the surface to the moving object.

For the calculation of magnitude of normal reaction:

[tex]v^2=u^2+2as[/tex]

Substituting the values of the initial velocity (u), final velocity (v) and the distance (s) at the contactless surface, the acceleration is given as:

[tex]0=(5)^2+2a\;\times\;4\\a=3.125\;\rm m/s^2[/tex]

The force can be given as:

[tex]F=ma\\F=80\;\text{kg}\;\times\;3.125\; \rm {m/s^2}\\\textit F=250\;N[/tex]

The magnitude of reaction for the wheel is 250 N.

The coefficient of friction ([tex]\mu_k[/tex]) is given as:

[tex]\mu_kmgs=\dfrac{1}{2}mv^2\\[/tex]

Substituting the values:

[tex]\mu_k\;\times\;80\;\times\;9.8\;\times\;4=\dfrac{1}{2}\;\times\;80\;\times\;5^2\\\mu_k=\dfrac{5^2}{2\;\times\;9.8\;\times\;4}\\\mu_k=0.32[/tex]

The coefficient of kinetic energy between the wheel and ground is 0.32.

Learn more about kinetic energy, here:

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