A certain gas has a volume of 10 liters at a temperature of 404 kelvins (k) and a pressure of 36 pascals (pa). if the temperature is raised to 450 k and the pressure is raised to 40 pa, what is its volume? to the nearest liter, the volume is liters.

Respuesta :

The final volume of the ideal gas is 10.02 liters.

Given Initial volume V₁=10 liters

Initial temperature T₁=404K

Initial pressure P₁ = 36 pascals

Final volume = V₂

Final temperature T₂ = 450K

Final pressure P₂ =40 pascals

What is the ideal gas equation?

The ideal gas equation with usual notations is given by:

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

So, [tex]\frac{36*10}{404} =\frac{40*V_2}{450}[/tex]

[tex]V_2=[/tex]10.02 liters

Hence, the final volume of the ideal gas is 10.02 liters.

To get more about the ideal gas visit:

https://brainly.com/question/20348074

Answer:

10 liters

Step-by-step explanation:

i like boys