The ground speed (G) is given as
.[tex]G=\sqrt{(600\dfrac{\sqrt{3}}{2}+20)^2+(300+40\dfrac{\sqrt{3}}{2}})^2}[/tex]
The correct potion is B.
The quantity which has magnitude, direction and follows the law of vector addition is called a vector.
An airplane is flying in the direction of 30 degrees South of West at 600 mph. A wind is blowing in the direction of 60 degrees North of East at 40 mph.
It means the airplane is flying in the opposite direction of the wind.
The component of an airplane will be
[tex]x=-600sin30\\\\x=\dfrac{-600}{2}=-300\\\\y=-600cos30\\\\y=\dfrac{-600 \sqrt{3}}{2}}[/tex]
The component of wind will be
[tex]x=40cos60\\\\x=\dfrac{40}{2}=20\\\\y=40sin45\\\\y=\dfrac{40\sqrt{3}}{2}}[/tex]
Then the ground speed will be
.[tex]G=\sqrt{(600\dfrac{\sqrt{3}}{2}+20)^2+(300+40\dfrac{\sqrt{3}}{2}})^2}[/tex]
Then the correct potion is B.
More about the vector link is given below.
brainly.com/question/13188123
