Respuesta :
The percent yield of oxygen if 10.2 g of O₂ is produced from the decomposition of 17.0 g of H₂O is 67.6%.
How do we calculate moles from mass?
Moles (n) of any substance can be calculated by using their mass as:
n = W/M, where
W = given mass
M = molar mass
Given chemical reaction is:
2H₂O → 2H₂ + O₂
Moles of 17g H₂O = 17g / 18.02 g/mol = 0.943 moles
From the stoichiometry of the reaction it is clear that,
2 moles of H₂O = produces 1 mole of O₂
0.943 moles of H₂O = produces 1/2×0.943=0.471 mole of O₂
Now mass of this 0.471 moles of O₂ = (0.472mol)(32g/mol) = 15.104 grams
Actual mass of oxygen = 10.2g (given)
Now on putting vales on the percent yield formula, we get
% yield = (10.2 / 15.104)×100% = 67.53% = 67.6%
Hence the required value of percent yield is 67.6%.
To know more about percent yield, visit the below link:
https://brainly.com/question/25996347
